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Use elimination to solve the system of equations. Find ordered pairs. { 5x-3y=42 8x+5y=28
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Multiply the top equation by 5 Multiply the second equation by 3 Add the two equations.
25x-15y=210 24x+15y= 84 49x = 294 Now divide both sides by 49
What does x = ?
x=6 right?
yes. Now find y
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how do i find y?
Replace x with 6 in any equation that has both an x and a y and solve that equation for y
so like 5x-3(6)=42?
I believe you said that x = 6. So why did you replace y with 6 if it is x that is equal to 6?
oh! so it would be 5(6)-3=42 i don't understand how to do these problems with elimination, I only know how to do them as substitution.
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What happened to the y?
|dw:1327614823096:dw|
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