Question

Please help me in factoring this expression:
25a^2 - 9b^2 - c^2 + 6bc.

Answer 1

(5a)^2-(3b-c)^2
=(5a+3b-c)(5a-3b+c)

Answer 2

How did you get 3(b - c)^2?

Answer 3

\[25a^2-(c^2-6bc+9b^2)\]\[25a^2-(c-3b)^2\]

Answer 4

no its 3b-c

Answer 5

\[(5a+3b-c)(5a-3b+c)\]

Answer 6

Is it 3b - c or c - 3b?

Answer 7

yeah i gave the same thing...pratu use a-b whole square formula.....3b-c

Answer 8

he didnt factor out the minus sign like i did

Answer 9

i did

Answer 10

so it doesnt matter, both work

Answer 11

You both got the same answer.

Answer 12

why cant it be -(9b^2+c^2-6bc)?

Answer 13

its the same:S

Answer 14

Thanks lalaly and king.

Answer 15

kk!

Answer 16

i showed u how i got it, so hope it helps

Answer 17

yeah actually (a-b)^2 is same as (b-a)^2

Answer 18

It did help lalaly, thanks.

Answer 19

:) anytime

Answer 20

\[(5a)^{2}-(3b-c)^{2}\]