10 years hence, A will be twice as old as B was 10 years ago. If A is now 10 years older than B, find the present age of B. I formed this equation for solving this sum: x + 9 + 10 = 2(x - 10) Where x + 9 is A's age and x is B's age. Just wanted to know if I am right.
I got B's age as 39. Am I right??
is this the full question?
Yes it is.
A+10=2(b-10)
or actually, it's kind of confusing
10 years from the future or the present?
x + 9 + 10 denotes A's age 10 years hence. It is equal to 2(x - 10) which is twice of B's age 10 years ago.
im confused too
i guess ten years ago from 10 years in the future is the present, lol
You have a point there.
But then, they've given 10 years hence for A and 10 years ago for B.
Pretty sure the original equation i gave is correct
where did you get x + 9 from?
Which is same as mine right? Only thing I've replaced A with x + 9.
Well actually, they're not the same
x + 9 is A's present age(B's present age is x and A is 9 years older than B) .
I don't see anything about a 9 in the question...
Oh, I made a typing mistake its actually if A is 9 years older than B, find B's present age.....
Can you tell how? Because on solving the equation, I got 39 .....
let me double check
I'm sorry, you are right. B is presently 39 years old.
Thanks for helping.
A+10=2(B-10) A=2B-30 A=B+9 B+9=2B-30 B=39
No problem
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