Question

Find x intercepts? y=3x^2+11x-4. Do I solve for y then substitute?

Answer 1

set y=0 then solve

Answer 2

Y=0 for x intercepts.

Answer 3

let y = 0

Answer 4

What does that mean?

Answer 5

\[\min{y = 3 x^2+11 x-4} = -169/12 at x = -11/6 \]

Answer 6

am i correct ?

Answer 7

3x(x+4)(-1(x+4)=3x-1=0=1/3 and x+4=0=-4 coming to: -1/3,-4 is this right?

Answer 8

or is this only y?

Answer 9

it also -11/6

Answer 10

and that the possible answer.

Answer 11

I assume you made a typo
3x-1=0=1/3 and x+4=0=-4 coming to: -1/3,-4 is this right?
because the answer is +1/3 (which you found, but then typed in -1/3)
@142343 x= -11/6 is where the parabola reaches a minimum, but its y-value at x= -11/6 is not zero. The question is asking for the 2 points where the parabola crosses the x-axis