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Can anyone tell me how to solve this problem without using a reduction formula. I have the answer, I just don't know how to get there. Thanks!
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The answer is stuff written in the green box btw
\[2sin{a} \times cosb=sin(a+b)+sin(a-b)\]
Is that a commonly known trig identity? I am not familiar with that one.
well it is 1 of 12 in my book, i never remember any of these but i reckon it will work because sine integrates to cosine which is the form of your answer
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cool beans, thanks
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