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What is the equation in point-slope form of the line passing through (0, 5) and (–2, 11)
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first find the slope, do u know how?
no
ok the slope is equal to\[\large{\frac{\Delta y}{\Delta x}= \frac{y_2-y_1}{x_2-x_1}}\]
\[=\frac{11-5}{-2-0}\]
Lala, we can further simplify it to: \[ = -\frac{7}{2} \] :P
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oops 2
No it's \[ =\frac{11-5}{-2-0} = -\frac{6}{2}\]
\[\frac{-6}{2} = -3\]
y – 5 = –3(x + 2) y – 5 = 3(x + 2) y – 11 = –3(x – 2) y – 11 = –3(x + 2) were the options though :/
That's the hardest step lol
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yeah wer not done, i just showd u how to find the slope
Do u want to learn this or do u just want the answer?
Who wants to learn? :P here is the answer : \[ y – 11 = –3(x + 2) \]
Lol Ok FOOOL :P
haha :D
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thank you both *Bows down*
;)
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