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what number must be added to both the numerator and the denominator of the fraction 5/21 to give a fraction equal to 3/7?
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7
how?
(5+x) / (21+x) = 3/7
let the number be x....then (5+x)/(21+x)=3/7 crossmultiply 35+7x=63+3x 4x=28 x=7
let the number that you must add be called x. on the top you have 5+x while on the bottom you have 21+x together they must form a fraction equal to 3/7
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(5+x)/(21+x)=3/7 crossmultiply 35+7x=63+3x 4x=28 x=7
^Quit cheating -_-
fine then
Just stop. -.-
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why
u stop
lol
now all we need is a "let me wolframalpha that for you" site
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