Question

Need help
please show me the steps so i know how to do this. Thanks.
-4(x^-3y^-1)^-2

Answer 1

\[-4(x ^{-3y ^{-1}})^{-2}\] ???

Answer 2

just put the y^-1 down like the x is

Answer 3

what?

Answer 4

\[-4(x^{-3}y^{-1})^{-2}\]

Answer 5

?

Answer 6

yes akshay

Answer 7

ok so we go on solving using the basic equation \[x^{-a}={1 \over x^a}\]

Answer 8

-4 x^6 y^2?

Answer 9

so we have \[x^{-3}={ 1 \over x^3} , y^{-1}={1 \over y^1}\]

Answer 10

similarly we have\[(x^{-3}y^{-1})^{-2}={1 \over(x^3y)^2}\]

Answer 11

so your answer is
\[-4 x^6y^2\]

Answer 12

sorry for late replies, net problem

Answer 13

is it clear?

Answer 14

yes thank you i get it. thanks for all the steps