Question

Find the distance from the point (2,-1) to the line y = 2x + 3

Answer 1

y = -1/2 x +(2)/2 - 1

y = -1/2 x seems to be the line with the point on it

system of equation to find the intersection then distance it from point to point

Answer 2

2x+3 = -1/2 x

5/2 x = -3

x = -3/(5/2) = -6/5 maybe :)

Answer 3

-1/2 * -6/5 = 6/10 = 3/5 then

2(-6/5) + 3 = -12/5 + 15/5 = 3/5

so thats a match

Answer 4

My correct answer says : 8/5 * sqrt(5), could you help me to get there?

Answer 5

(10/5, -5/5)
- (-6/5 , 10/5)
---------------
(16/5)^2 + (-15/5)^2

sqrt(16^2+15^2)/5 should be it then

Answer 6

seeing how i thought my first explanation was suffieicnt; youll have to address where it is your following goes amiss at

Answer 7

other than typos :)

Answer 8

y = 2x + 3 needs a perp line to it; perp line is just flip and negate the slope

2 flips to -1/2

y = -1/2 x + b ; use (2,-1) to calibrate

2 = -1(-1)/2 + c

2 = 2 + c ; c = 0

y = -1/2 x is equation of line perp to and containing (2,-1)

Answer 9

if we know where the lines meet, we have a point of reference to measure distance with ...

Answer 10

y = 2x + 3
-( y = -1/2 x)
-------------
0 = 5/2 x + 3 ; when x = -3/5

Answer 11

y = -1/2 * -3/5 = 3/10

therefore, point of intersection is: (-3/2 , 3/10) looks better

Answer 12

(-3/5 , 3/10) that is