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h=.5cos(2t) where t is time in seconds and h height in feet, is the instantaneous velocity t=2 greater than or less than .76?
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velocity is dh/dt dh/dt = -2(.5) sin(t) = -sin(t) at t=2, -sin(2) = -.909 < .76
oh it doesnt want me to use derivatives or limits
how can you find the instantaneous velocity then?
i first started making a table and taking the average velocity at points closer and closer to 2
yeah and as you get closer and closer to 2 the limit of the slope or velocity is the derivative
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well the way i was doing i didnt technically use a derivative or limit i just dont think i was doing it right
this is what i was doing
here is what it should look like
thank you very much
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