Question

How would you solve 3onthesqrt(4x-4) +2 =0

Answer 1

\[\sqrt[3]{4x-4} +2 = 0\]

Answer 2

\[\sqrt[3]{4x-4} +2 = 0\]
\[\sqrt[3]{4x-4} =-2\]
\[(\sqrt[3]{4x-4})^3 =(-2)^3\]
\[4x-4=-8\]
\[4x=-4\]
\[x=-1\]

Answer 3

Thanks, but it wants to know how many solutions there would be as well, so would it be one or?

Answer 4

only one solution

Answer 5

thank you so much
precalc homework.. it's about to be a long semester

Answer 6

yw