A camper has 3 jackets, 6 sleeping bags, and 14 different packages of food. An outfit consists of 2 jackets, 2 sleeping bags, and 3 packets of food. How many ways can the trip be outfitted?______
much easier than the last one
Similar to the other one right?
\[\dbinom{3}{2}\times \dbinom{6}{2}\times \dbinom{14}{3}\]
is it clear how to compute these numbers, because in fact all i really did was restate the question in notation
how exactly do i solve that notation? multiply? Cross multiply?
sorry it has been forever since i had a math class now im in this finite course:)
maybe you have seen it this way instead \[3C2\]?
yes
3x2x1 ----- 2x1 ?
number of ways to choose 2 from a set of 3 is 3 number of ways to choose 2 from a set of 6 is \[\frac{6\times 5}{2}=15\]
how do u get the 6 and 5
yes that is one way to think about it. the other way is more basic. if you have three items and wish to select one, you pretty clearly have 3 choices. if you have three items and wish to select 2, you have the same three choice ( like selecting the one to exclude)
you have 6 sleeping bags and wish to select 2 of them, six choices for first bag, 5 for second and you have to divide by two because order doesn't count
the last one is therefore \[\frac{14\times 13\times 12}{3\times 2}\]
so there are only two then correct?
two what?
are there two cases for this
for this problem it is a straightforward multiplication \[\dbinom{3}{2}\times \dbinom{6}{2}\times \dbinom{14}{3}\] \[3\times 15\times 364\]
wow you are a genius 16380
but....im not sure how you got 3x15x364 what do i do with the numbers inside ( ) exactly?
got disconnected
Join our real-time social learning platform and learn together with your friends!