Question

3kHC2O4.H2O=
MOLAR MASS

Answer 1

This is the same as the previous problem you posted. Try going through a similar process as the one I showed there, and see what answer you come up with.

Answer 2

please help me,i got 438.3 as my molar mass here,just wanna be sure if my solving is right cos i will be doing a long calculation of limiting reagent with it.if i miss the molar mass,the whole thing will be wrong

Answer 3

I just want to make sure I'm reading it correctly. The formula is this, correct?\[3KHC_2O_4·H_2O\]

Answer 4

yeah exactly

Answer 5

I got 402.53g*mol^{-1}.

Could you go ahead and show your work and I can see where you got off?

Answer 6

ok

Answer 7

3*(39.1+1+24+64+2+16)

Answer 8

=438.3g/mol

Answer 9

There aren't 3mols of the H2O, unless the equation is actually written like this...\[3(KHC_2O_4·H_2O)\]Otherwise, if it's like I wrote it above, it the math should like something like this...\[3*(39.1+1+24+64)+1*(2+16)\]

Answer 10

oh! ok,i now see my mistake thanks