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Let c be any constant number. Which of the following will always be perpendicular to −3x + y = −1?
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y equals one over three times x plus c y equals negative one over three times x plus c y equals negative three x plus c y equals three x plus c
Two perpendicular lines (neither horizontal or vertical) have slopes that multiply to -1. The given line −3x + y = −1 has a slope of 3. Place in y = mx + b form to get y = 3x -1. Look for a choice that has -1/3 as its slope. y equals negative one over three times x plus c which is y = (-1/3) (x) + c.
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