Question

limit of x is 9, find the limit, radical x -3/x-9?? i need step by step please!!!

Answer 1

\[\lim_{x \rightarrow 9} \sqrt{x}-3/x-9\]

Answer 2

well simply subsitution wont work,
try L'Hôpital's rule

Answer 3

\[x-9=(\sqrt{x}+3)(\sqrt{x}-3)\]

Answer 4

thats a hint

Answer 5

or what myininaya said, probably easier for this example

Answer 6

how did you get to that point tho? radicalx+3 -3 i mean

Answer 7

difference of squares

a^2 -b^2 = (a+b)(a-b)

(sqrtx)^2 - 3^2 = (sqrtx +3)(sqrtx -3)