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what is the mass in grams of 2.90x10^12 lead (Pb) in atoms ?
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What is the atomic weight of Pb?
207.2
\[2.90\times 10^{12}atoms Pb \times\frac{1 mole Pb}{6.023\times 10^{23}atoms Pb}\times\frac{207.2 g Pb}{1 mole Pb}\]
I think that works out to 9.98 x10^-10
how do you figure out the correct scientific notation ?
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I just plug it into my calculator
But if you can't do that then do this:
\[\frac{2.90(207.2)}{6.023}=99.8\]
Now we must do the powers of 10
\[\frac{10^{12}}{10^{23}}=10^{-11}\]
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So now we have: \[99.8\times 10^{-11}\]
thank you !!
And we need to put that into scientific notation. Can you do that?
yes sir/ma'am
Good for you.
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