Question

n=4; 3 , 1/3 and 1+2i are zeros

Answer 1

...

Answer 2

write it in factored form:

however with complex roots, do the following
x = 1 +-2i
x-1 = +-2i
(x-1)^2 = 4i^2 = -4
(x-1)^2 +4 = 0
x^2 -2x +5 = 0

--> (x-3)(x-1/3)(x^2 -2x +5)
Now just multiply it out

Answer 3

also if you don't want to deal with fractions:

x = 1/3
3x = 1
3x-1 = 0

Replace (x-1/3) with (3x-1) since they both yield the same zero of x=1/3

Answer 4

ok thank you