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Find the zeros of the function f(x) = x2 +9x + 20 by factoring.
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-4 -5
Remember the form \[ax ^{2}+bx+c\] Now, the numbers that you factor out must multiply to be c, but add to equal b. So, the numbers we want here must multiple to equal 20 and add to equal 9.
f(x)= (x2+4)(x+5)
(x+___)(x+___) And as the others have graciously told you, yes. 4, 5
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