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Mathematics 22 Online
OpenStudy (anonymous):

How would you find the standard equation of a circle, inscribed inside a square with the verticies (-12,10), (8,10), (8, -10), (-12,10)?

OpenStudy (mertsj):

well at least we know that the radius of the circle is 10

OpenStudy (mertsj):

The midpoint of the diagonals is (-2,0) and that would be the center of the circle so the equation must be:

OpenStudy (anonymous):

wouldn't that be the diameter?

OpenStudy (mertsj):

\[(x+2)^2+y^2=100\]

OpenStudy (mertsj):

Wouldn't what be the diameter?

OpenStudy (mertsj):

|dw:1328498116730:dw|

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