Write an equation of the line that passes through the given point and is (a) parallel to the given line and (b) perpendicular to the given line.
(6,0), y= 3/4x -1/4

Question

Write an equation of the line that passes through the given point and is (a) parallel to the given line and (b) perpendicular to the given line. 
(6,0), y= 3/4x -1/4

lgbasallote · Answer

PARALLEL:
slope = 3/4

equation of the line = y = 3/4(x-6)

4y = 3x - 18
3x - 4y -18 = 0

PERPENDICULAR:
slope = - 4/3

equation of the line: y = -4/3(x-6)

3y = -4x + 24
4x + 3y -24 = 0

anonymous · Answer

Parallel:
$$y=\frac{3}{4}(x-6), y=\frac{3}{4}x-\frac{9}{2}$$
Perpendicular:
$$y=-\frac{4}{3}(x-6),y=-\frac{4}{3}x-8$$

anonymous · Answer

$$y=-\frac{4}{3}x+8$$,  not minus, sorry about that

anonymous · Answer

THANKS <3

anonymous · Answer

The Parallel is always the same slope and then the Perpendicular is always the reciprocal of the slope. :)