Question

In the equation of the circle (x-5)^2+(y-5)^2=50,does it touches with the origin?Find the center of the circle?

Answer 1

>>In the equation of the circle (x-5)^2+(y-5)^2=50,does it touches with the origin?

Put x=0 and y=0 and it's satisfies the equation so it does.


>>Find the center of the circle?

(5,5)

Answer 2

Centre (5,5) so draw a right triangle.... and see if the hypotenuse is equal to the radius.



\[r = 5\sqrt{2}\] from the circle equation

using Pythagoras 's theorem.. 5^2 + 5^2 = ch^2

ch ^2 = 50... sam as sth

Answer 3

tHE hypotenuse is \[h = 5\sqrt{?}\] the same as the radius so the circle touches the origin

Answer 4

? = 2