Question

i need help answering this
3*(sq rt of 48) + 2*(sq rt of 12)

Answer 1

\[16\sqrt{3}\]

Answer 2

how do u solve

Answer 3

\[3\sqrt{48}+2\sqrt{12}\]
\[12\sqrt{3}+4\sqrt{3}\]
\[16\sqrt{3}\]

Answer 4

You need to factor out the perfect squares 48 is 3 * 16 which the 16 is 4 * 4 and 12 is 4 * 3 so you can factor the 4 out as 2 * 2 which leaves you with what sritama said.

Answer 5

u explain it better than the book does

Answer 6

Thanks

Answer 7

y is is 12(sq rt of 3) instead of 16(sq rt of 3) ????