Write an equation of the line that contains the median of triangle RST from S to line RT. R(-2,-2) S(1,4) T(7,1)
the median from point S to line RT divides the line RT in half. Can you find the mid point of (-2,-2) and (7,1)?
the midpoint i got was (5/2,-1/2)
do you know how to find the equation of a line given 2 points? S (1,4) and mid pt (5/2, -1/2)
one way is find the slope: change in y divided by change in x then use one of the points to find b in the equation y= mx+b
i was thinking altitude, not median
i got y=-3x+7
now i need to show that the median of the triangle from S is also the altitude from S. how do i do that?
an altitude forms a right angle. that means the lines RT and the medians have slopes m and -1/m so find the equation of the line through R and T, it's slope should be 1/3
or just find the slope between R and T. don't really need the entire equation
just to be clear: perpendicular lines have slopes m and -1/m
yeah the reciprocal but i already said what the slope between R and T. is (5/2,-1/2)
that is the mid point. the slope is different (for starters, slope is a number, not a pair)
the slope is 3/5?
R(-2,-2), T(7,1) change in y divided by change in x (1 - (-2))/(7 - (-2))= 3/9 = 1/3
You must know how to find the slope, because you found it for the median line.
oh i forgot it was a -2 so um now what do i do?
you write down: slope of the line RT is 1/3 slope of line from S to mid pt of RT is -3 -3*1/3 = -1 therefore they are perpendicular, and form a right angle. A line from a vertex to the opposite leg that forms a right angle is an altitude.
is that a negative sign before the first 3?
no it is a minus sign (just kidding). It is -3, the slope of the median line.
um isn't -3 -3*1/3= -2?
you said i got y=-3x+7, so its slope is -3 and we found the slope of R to T is 1/3 so the slopes are negative reciprocals -3 * 1/3 = -1 so the lines are perpendicular. that means your median line is also an altitude.
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