Question

Peter's walking speed is 1.5 m/s, while Davis's walking speed is 1 m/s. (a) If they start walking away from each other, how long will it be for them to be 100m apart?
(b) If they start walking in the same direction at the same time, how long will it be for them to be 100 m apart?

Answer 1

A) Let the time taken for them to be 100 m apart = x seconds
in this time
Peter covers 1.5x m and Davis covers 1x m
ATQ, 1.5x + x = 100
2.5x = 100
x = 100/2.5 = 40
so they will be 100 m apart after 40 seconds

Answer 2

A) When they walk in the same direction,
Let the time taken for them to be 100 m apart = x seconds
in this time
Peter covers 1.5x m and Davis covers 1x m
Since Peter's speed is more, he will be ahead

ATQ, 1.5x - x = 100
0.5x = 100
x = 100/0.5 = 200
so if they walk in the same direction, they will be 100 m apart after 200 seconds i.e. 3 min 20 seconds