Question

one leg is x and the other is h and the hypotenuse is 2x and i have to solve for h and i got just x did i do this right?

Answer 1

This is a special right triangle, 30-60-90

Answer 2

yes and how can we use that to solve this problem ?

Answer 3

What do we know about 30-60-90 right triangles?

Answer 4

the hypotenuse is 2x the shortest side and the other leg is x times the squareroot of 3

Answer 5

Exactly

Answer 6

So what is h?

Answer 7

h= x squareroot of 3

Answer 8

right

Answer 9

but cant you use pythagorean theorem as well

Answer 10

Yes.

Answer 11

but how can we do that b/c it says use an algebraic expression

Answer 12

\[h=\sqrt{(2x)^2-x^2}=\sqrt{4x^2-x^2}=\sqrt{3x^2}=x \sqrt{3}\]

Answer 13

see?

Answer 14

yes i get it thanks a lot

Answer 15

you're welcome