Question

pleaseeeee help!

The one-to-one functions g and h is defined as follows:
g= {(-7,4),(-5,1),(-4,7),(7,-9)}
h(x)=3x+8

find:
g^-1(7)=
h^-1(x)=
(h o h^-1)(-7)=

Answer 1

g={(-6,-2),(-2,-5),(7,5),(9,7)}
h(x)=2x+9

find:

g^-1(-2) = ?
h^-1(x) = ?
(h o h^-1)(7) = ?

Answer 2

kumar please post your question in a new thread..

Answer 3

?

Answer 4

g^-1(x) is g inverse. When you have an inverse function, it means that the x and y values of your original function switch. So just switch all the x and y values for g(x) to get g^-1(x). This means g^-1(x) = {(-2,-6),(-5,-2),(5,7),(7,9)} From the points, we can see g^-1(-2) = -6.

h^-1(x) is h inverse. So to figure out what the inverse function is, switch x and h(x) and solve for h(x), which becomes the inverse function. h(x) = 2x+9 becomes x = 2h(x)+9
x-9 = 2h(x)
(x-9)/2 = h(x)
Now because we solved for the inverse function, change h(x) to h^-1(x) = (x-9)/2

(h o h^-1)(7) is the same as h(h^-1(7)). From the previous problem, h^-1(x) = (x-9)/2, so we can substitute: h((7-9)/2) = h(-1) = 2(-1)+9 = 7

Answer 5

thats not my question though... those are wrong numbers