solve the integral (14x+1)/(4x^2-13x-12) .. please help guys .. no one is answering me lately =[ and tomorrow i have a test !!!!
is the top the derivative of the bottom?
nope ... because you have 13x downstairs and on top 1
good, then most likely we have to do a decomp whats the fators of the bottom?
factors even
i didin't manage to find real roots from the quadratic equation ...
let me chk that then 4x^2-13x-12 13^2-4(4)(-12) = 196+ some value it doesnt go complex
oh yes you are right !!!! i did a mistake with the minus sign !!! any way can you just tell me how to factor when you find the roots ? =]
\[\frac{14x+1}{4x^2-13x-12}=\frac A{4x+3}+\frac B{x-4}\]
16 and 3 (x-16/4)(x+3/4) (x-4)(4x+3)
youhave a test, how is just telling you going to give you the means to solve it? that comes from experience .... hands on stuff
turing gave the split up; now we have to solve for A and B
we do that by trying to recombine the fractions using the unknowns and comparing it with the known numberator
yes ... i see ... thank you very much !!
14x + 1 = A(x-4) + B(4x+3) the simple means here is to zero one of the terms out; when x=4 we get A(0) sooo 14(4) + 1 = B(4(4)+3) B = 57/19 if i see that right :)
B cancels out when x = -4/3
yes !! thank you i can go on from here peacfully =] .. i will be happy for help with my other questions from the last 2 hours that no one replied yet ;]
if you repost it we will be able to find it easier, with any luck :)
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