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Rearrange the equation W=F(triangle)d to express F by itself and (triangle)d by itself.
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You have to solve \[\ W=F \Delta d \] for F and for (triangle)d (that triangle is a greek letter called delta) What that means is that you have to "isolate" F on the one side of the equation and have something else on the other. Do the same for \[\ \Delta d\]
that triangle is called delta or change in some quantity
yes, I know I should have put that instead.
and um, is it: F = W/delta d?
You got it...
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delta d = W/F?
yup...
thanks!
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