A 10.0 µF capacitor has plates with vacuum between them. Each plate carries a charge of magnitude 1180 µC. A particle with charge -3.00 µC and mass 2.00x10^-16 kg is fired from the positive plate toward the negative plate with an initial speed of 2.00x10^6 m/s.

Question

jamesj · Answer

So what's the question?

anonymous · Answer

How exactly do you go about doing this?

jamesj · Answer

What I mean is: you've set up a scenario.  But what is it that you now want to find out?  What is it you are trying to calculate?

anonymous · Answer

sorry i missed part of the question when i pasted it, what is the impact speed?

jamesj · Answer

Ok. As the charge moves across the plates work is done on it. Have a look at this question for the equation for work: http://openstudy.com/study#/updates/4f419fb4e4b0803c635309f1 You can calculate the potential difference, V, between the plates by using the definition of capacitance: C = Q/V. That work is transformed into change in kinetic energy. Use that change in kinetic energy to find an expression involving the final kinetic energy of the particle, call it v. You have all the other variables you need (V, q, m) in order to solve for v.

jamesj · Answer

Make sense?

anonymous · Answer

yup thank you

jamesj · Answer

great.  

And a belated welcome to Open Study!