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Physics 18 Online
OpenStudy (wasiqss):

another complex circuit f

OpenStudy (ash2326):

where is it?

OpenStudy (wasiqss):

OpenStudy (anonymous):

What are we solving for?

OpenStudy (wasiqss):

In ,Is ,Vx

OpenStudy (wasiqss):

|dw:1329939821707:dw|

OpenStudy (anonymous):

Which voltage is the current source on the right tied to?

OpenStudy (anonymous):

Vx?

OpenStudy (wasiqss):

lalaly solve it plz

OpenStudy (lalaly):

okay wait

OpenStudy (lalaly):

\[I_{IN} =\frac{v}{r}=\frac{4}{2}=2A\]

OpenStudy (wasiqss):

what is Is

OpenStudy (anonymous):

What is that on the far right?

OpenStudy (wasiqss):

dependent voltage source

OpenStudy (anonymous):

Doesn't look like a voltage source but ok, and what is Is.Is it a current source ?

OpenStudy (wasiqss):

yes an independent current source

OpenStudy (anonymous):

Is = 2A

OpenStudy (anonymous):

Vx = -4V

OpenStudy (wasiqss):

how? and btw In is current coming from externtal source

OpenStudy (anonymous):

so I_in is not 2 A?

OpenStudy (wasiqss):

i guess not

OpenStudy (anonymous):

ah, I see now...It is bad drawing. Let me start again :D

OpenStudy (anonymous):

but Vx should be correct

OpenStudy (wasiqss):

ohhh really?

OpenStudy (anonymous):

Are you sure that that on the right is the dependent voltage source, because it does have an arrow in it.

OpenStudy (wasiqss):

it is having arrow from bottom to to

OpenStudy (anonymous):

I think it is a voltage dependent current source. At least by the usual convention. wasiqss. Could you take a picture of the diagram with a camera so we can better understand the problem?

OpenStudy (anonymous):

Yea that would be nice. It has to be a current source, otherwise you get -16V on that source which cannot be true since there is a voltage drop of 8V on the resistor connected parallel to it.

OpenStudy (anonymous):

IF that actually is a voltage dependent current source, and I_in is coming in from the outside, I mean, I_in is not the same current flowing through the left-most resistor, I got some values. Vx=-4v, I_in=20A, Is=22A. I didn't check it or anything so it might be wrong.

OpenStudy (anonymous):

And I took that voltage dependent current source as 4*Vx

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