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Mathematics 18 Online
OpenStudy (sasogeek):

\[\huge \text{Prove that } log_{a}{x}+x^2+...+x^n=nlog_{a}{x} \]

OpenStudy (anonymous):

prove it? i can't even see it..

OpenStudy (sasogeek):

lol

OpenStudy (sasogeek):

I already did the first 4... the last one is what I posted

OpenStudy (anonymous):

i don't think it is correct

OpenStudy (anonymous):

\[n\log_a(x)=\log_a(x^n)\] so unless \[x+x^2+...+x^n=x^n\] this cannot be correct

OpenStudy (anonymous):

you can even try it with numbers if you like and see that it does not work

OpenStudy (anonymous):

yes, exactly, this is not correct.

OpenStudy (sasogeek):

thank you :)

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