Question

\[\huge \text{Prove that } log_{a}{x}+x^2+...+x^n=nlog_{a}{x} \]

Answer 1

prove it? i can't even see it..

Answer 2

lol

Answer 3

I already did the first 4... the last one is what I posted

Answer 4

i don't think it is correct

Answer 5

\[n\log_a(x)=\log_a(x^n)\] so unless
\[x+x^2+...+x^n=x^n\] this cannot be correct

Answer 6

you can even try it with numbers if you like and see that it does not work

Answer 7

yes, exactly, this is not correct.

Answer 8

thank you :)