Each digit of a 10-digit number N is either a 1,2,or 3. Every 3 consecutive digits of N form a prime number. find the final two digits fo the smalles such N.

Question

istim · Answer

IsTim IsStumped.

albertrea · Answer

lol

cwrw238 · Answer

for smallest N first 3 digits would be 113 - dont know if that helps!!!

cwrw238 · Answer

so - maybe its 32?

cwrw238 · Answer

1131131132

cwrw238 · Answer

assuming 113 is prime - i think it is

albertrea · Answer

the last two could be 2,3 or one 1,3 , what you thing?

cwrw238 · Answer

r u saying those are the options?

albertrea · Answer

sorry , the options are 11, 13, 21, 23,31

albertrea · Answer

just saying that give that they mean the form of a prime number , now that I rethink it, its just anything beside two that I narrow it down

cwrw238 · Answer

i'm puzzled - there has to be at least one 2 in the number right?
my number cant be right because 132 is divisible by 2

cwrw238 · Answer

i cant see where the 2 would be - maybe it has to be the first number - yes it has to be

cwrw238 · Answer

so how about
2113113113

cwrw238 · Answer

i think 211 is prime

cwrw238 · Answer

and 311 and 113

cwrw238 · Answer

131 is also prime 
i think we have it guys
the last 3 numbers cant be 111, nor 131  - they must be 113

cwrw238 · Answer

last two digits are 13