Which point is the vertex of the parabola y = x2+4x+1? A. (-2, -3) B. (2, 3) C. (-2, 3) D. (2, -3)
Agreed^
thanks :P
A only
??
how many vertices does this one poor quadratic have?
satellite just post your solution
dunno. pick all 4 because apparently there can be more than one
Nah,vertex is singular, plural would be vertices lol
Once again, that's not a solution sat
I'm sticking with A = (-2,-3)
I agree with Hero (A)
@belaski \[x=-\frac{b}{2a}=-\frac{4}{2\times 1}=-2\]is the first coordinate second coordinate is \[(-2)^2+4(-2)+1=4-8+1=-3\]
well your only suppose to chose 1
satellite just didn't want to give me any credit
so answer is \[(-2,-3)\] trust me, i am a carnival barker
ok well thanks guys
Mancake, prove that your original answer is correct. Only then will I believe you to be a professor.
I think prof. mancake is right
I just used the same formulas and i got the same answers
A. (-2, -3) y = x2+4x+1 h = -4/2 = -2 k = (-2)^2 -4* 2 + 1 = -3
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