Question

convert each equation to standard form by completing the square on x and y. Then graph the ellipse and give the location of its foci.

4x^2+y^2+16x-6y-39=0

4x^2+25y^2-24x+100y+36=0

Answer 1

you need steps or answer?

Answer 2

first one is
\[4(x+2)^2+(y-3)^2=64\] or
\[\frac{x+2)^2}{1}+\frac{(y-3)^2}{4}=16\] and that put it in standard form for an ellipse

Answer 3

thank you