Question

1. When Richard plays tennis, 65% of his serves go into the correct area of the court. If the first serve goes into the correct area, his chance of winning the point is 90%. If his first serve does not go into the correct area, Richard is allowed a second serve, and of these, 80% go into correct area. If the second serve goes into the correct area, his chance of winning the point is 60%. If neither serve goes into the correct area, Richard loses the point.
iii. Find the conditional probability that Richard’s first serve went into the correct area, given that he loses the point.

Answer 1

wow i did this last year :D

Answer 2

wait i ll do it after finishing my game

Answer 3

onditional probability=(first serve went into correct area and he loses)/(he loses the point)

Answer 4

So... How do you calculate the probability of losing?

Answer 5

yes that imma tell u ok

Answer 6

in this we need to take in consideration in all the way he looses a point

Answer 7

Yes. So...?

Answer 8

ok im done, now tell me what is probability of he serving in the rite court first and losing a point

Answer 9

0.065?

Answer 10

exactly, now temme what is the probability of he serving first serve wronng and also second serve wrong?

Answer 11

0.07?

Answer 12

dang correct!, now temme what is the probability of he doing first serve wrong, and then second serve correct and he still lose a point?

Answer 13

0.112?

Answer 14

right again :), c u have actually solved the question on ur own :) , now jus put all the pieces together

Answer 15

conditional probability =(first serve went in and he lose a point)/(prob of serving in the rite court and losing a point+prob of serving in the wrong court both times+ prob of serving wrong first and then serving rite and losing again )

Answer 16

done it !

Answer 17

How did you know how to do it like that?