If you want to solve system of linear equation by substitution you ( for example ) : Equation (1) Equation (2) You find x in equation (1) and then substitute it in equation (2) and when you find y in equation (2) you substitute it in equation (1) ??
Aroub :O:O
:)(:
Yes! :D =D
lol, sounds confusing right? -.- Can you solve this one for me? ( with steps ) PLEASE =) 8x+4y=12 10x+5y=15
8x + 4y = 12 10x + 5y = 15 2x + y = 3 2x = -y + 3 x = -1/2 y + 3/2 10(-1/2 y + 3/2) + 5y = 15 -5y + 15 + 5y = 15 6 = 15 << no solution
both equations are same
oops, i half-updated some mistake should be 15=15
Oh I got that too! I thought I did something wrong :P lol thank youuu all :DD
8x+4y=12 is same as 2x+y=12 10x+5y=15 is same as 2x+y=12 So infinitely many solutions
Wait! It's no solution or infinite solution? O.o
infinitely many -- it'd be no-solutions if the numbers weren't equal (in the case I had before I changed to 15=15. x.x)
Aooh! Thank you :D
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