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Mathematics 6 Online
OpenStudy (anonymous):

Trigonometry: Verify the following: cot X +1/cot x - 1 = 1+ tan X/1-tanx I got as far as: ((cos x/sinx) +1)/((cos x/sin x)-1) but then got stuck. The answer key shows the next step is ((cos x +sin x)/sin x)/((cos x - sin x)/sin x) but I don't understand how we got there. Can someone explain?

OpenStudy (mertsj):

\[\cot x +\frac{1}{\cot x}-1=1+\frac{\tan x}{1}-tanx\]

OpenStudy (mertsj):

That's what you posted. What is the real problem?

OpenStudy (anonymous):

How is the grouping done for that? Whats in the numerator/denominator?

OpenStudy (anonymous):

numerator cot x + 1 and denominator cot x - 1

OpenStudy (anonymous):

next step I turned both cot into cos over sin

OpenStudy (anonymous):

the third step is the step I don't understand: numerator (cos x + sin x)/sin x and denominator (cos x - sin x)/sin x I don't understand where the ones went and where the sins in the numerator came from.

OpenStudy (mertsj):

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