Question

What are the coordinates of the vertex of the graph of the function y = –x² + 6x –11?


(3, –2)

(3, 16)

(–3, –29)

(–3, –20)

Answer 1

same equation applies here for the x-value of the vertex
x = -b/2a

we can then re-insert that value of x into our function to find the corresponding y-value

(-b/2a, f(-b/2a))

Answer 2

so in this case...
x= -(6) / 2(-1)
= -6/(-2)
= 3

-(3)^2 + 6(3) - 11
-9 + 18 - 11
9 - 11
-2

The point would be (3, -2)