Question

solve the equation. check both sides and only write the real solution(s).
radical 2x+3=x

A. -1
B. 3
C. -1,3

Answer 1

square both sides, solve the quadratic, make sure you test each zero to make sure they work in the original equation

Answer 2

\[2x+3=x^2\]
\[x^2-2x-3=0\]
\[(x-3)(x+1)=0\]
\[x=3, -1\]
\[\sqrt{2(3)+3}=3?\]
True, x=3 is a solution
\[\sqrt{2(-1)+3}=-1?\]
False, x=-1 is not a solution

Answer 3

but 3 would be correct
I was just workin on it and i got 3