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Find the nullity of T T: P_3 ->P_1, rank(T)=2
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Is the nullity 2?
poly3 to poly1 is what that means up there right?
rank = colA; which is the ...oppostie? of nullA
and of course polynomials have a n-1 caveat in there someplace
right
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wow thanks for coming i posted this a while back
so the nullity is 2?
p3 basis: [1,x,x^2,x^3] p1 basis: [1,x] T(p3) = A p3 A p3 = p1 a b c d 1 = 1 e f g h x x x2 x3 if rankT is 2, nullT is 2 if i see this right; any way to check it?
nope. I know what to do but like its polynomials so the only confusing part
yeah, polys tend to be a strange creature with vector spaces ....
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yes it si correct it must be
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