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Let P(x) = F(x)G(x) and Q(x) = F(x)/G(x), where F and G are the functions whose graphs are shown. http://www.webassign.net/scalcet7/3-2-050.gif (a) Find P '(2). (b) Find Q'(7).
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\[F'(2)=0\] since the tangent line is horizontal at that point, and \[G'(2)=\frac{1}{2}\] since at x = 2 G is a line with slope 1/2
now use \[(FG)'=F'G+G'F\] to get \[(FG)'(2)=F'(2)G(2)+G'(2)F(2)\] plug in the numbers and see what you get
i guess you also need that \[F(2)=3,G(2)=2\] by reading it off the graph
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