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Mathematics 7 Online
OpenStudy (lukecrayonz):

http://screensnapr.com/v/r76tj5.png

OpenStudy (lukecrayonz):

@TuringTest I feel like you'd like this problem a lot.

OpenStudy (lukecrayonz):

@Hero are you up for this one?:P

OpenStudy (turingtest):

not really a challenge if you know what they are asking for a vector of magnitude |V| at an angle theta, the component form is\[\vec V=|V|\cos\theta\hat i+|V|\sin\theta\hat j\]so just break out the calculator and calculate each component, i and j

OpenStudy (lukecrayonz):

|V| For this would be..

OpenStudy (lukecrayonz):

20?

OpenStudy (turingtest):

the length (magnitute) of the original vector yes, 20

OpenStudy (turingtest):

magnitude*

OpenStudy (lukecrayonz):

So 20cos(60)i+20sin(60)j?

OpenStudy (turingtest):

if they want it measured from 0 as north, then yeah

OpenStudy (lukecrayonz):

10i+10sqrt(3)j?

OpenStudy (lukecrayonz):

Or would theta be 30? Since it does state theta=30?

OpenStudy (turingtest):

oh I misread, 60 is 30 from north confusing lol they tell you straight out that theta is 30, so I think that's what you should use

OpenStudy (lukecrayonz):

20cos(30)+20sin(30)?

OpenStudy (turingtest):

yeah, I believe so

OpenStudy (turingtest):

i and j are important though

OpenStudy (lukecrayonz):

10sqrt(3)i+10j?

OpenStudy (lukecrayonz):

Strange, it just flipflopped.

OpenStudy (turingtest):

not strange\[\cos\theta=\sin(\pi-\theta)\]that's what happened here

OpenStudy (turingtest):

sorry\[\cos\theta=\sin(\frac\pi2-\theta)\]

OpenStudy (lukecrayonz):

I'll learn that after this assignment, right now i only have 30 minutes left to do a problem that only Amistre would get!:(

OpenStudy (lukecrayonz):

Well you might, not sure.

OpenStudy (lukecrayonz):

I'll post a new one.

OpenStudy (turingtest):

worth a shot

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