Question

http://screensnapr.com/e/789Sxq.png
Last question of the day!

Answer 1

Anything?:P

Answer 2

@amistre64

Answer 3

this is\[-1=e^{\pi i}=\cos\pi+i\sin\pi\]so that's a start...

Answer 4

I'm getting the third root of -1 to be\[(e^{\pi i})^{1/3}=\sqrt[3]1\exp(i(\frac\pi3+\frac{2\pi}3k));k=1,2,3,...\]\[=\cos\frac\pi3+i\sin\frac\pi3\]\[\cos\pi+i\sin\pi\]\[\cos\frac{5\pi}3+i\sin\frac{5\pi}3\]but you may want a second opinion, I was learning this on the fly
I may have misunderstood the question
good luck, gotta go

Answer 5

It's better than nothing, thank you so much!

Answer 6

My teacher knows I have no idea what to do for these, so I'm sure she'll be pretty lenient on my answers.

Answer 7

I heard of demoivre's before, i did a somewhat similar problem like a week ago, let me see..

Answer 8

bahrom drop this questionf or now

Answer 9

My newest question, checking my answers now