Question

how do i simplify x^2-16/ x+4 ?

Answer 1

\[\frac{x^2-16}{x+4}=\frac{(x+4)(x-4)}{x+4}=x-4\]

Answer 2

how did you do that?

Answer 3

What do you get when you factor x^2-16?

Answer 4

you get 1,2,4,8

Answer 5

x^2-16 is the difference of two squares and its factors are (x-4)(x+4)

Answer 6

Then cancel the common factor x+4

Answer 7

ok so then how would i solve \[y ^{2}+y-6/y ^{2}-4\] ? the factors of -6 are (x-2)(x+3)

Answer 8

And the factors of
\[y^2-4 are (y-2)(y+2)\]

Answer 9

x+3/y+2?

Answer 10

Cancel out the common factor y-2

Answer 11

yep

Answer 12

ok so how would i find the restrictions?