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Mathematics 19 Online
OpenStudy (anonymous):

Suppose that the cost to a manufacturer of producing x units of a certain motorcycle is given by C(x)= 220x+4000 where C(x) is in dollars. a) find the marginal cost B) find the cost of producing 500 motorcycles C) Use your answer in parts a and B to find the cost of producing 501 motorcycles.

hero (hero):

If I could have a dollar everytime I saw this question

OpenStudy (anonymous):

b. plug in 500 for x a derivative of C x = 220 Hero, I was thinking the same thing earlier today - they should have a buddy system going on

hero (hero):

A buddy system? What would that consist of?

hero (hero):

I need a buddy to go behind me and check my answers for mistakes.

OpenStudy (anonymous):

did i make a mistake

hero (hero):

I didn't say you did, however, I don't think this is necessary to be solved using derivatives. I doubt if Danyel even knows what derivatives are.

OpenStudy (anonymous):

quickest way to get marginal is via derivatives

OpenStudy (anonymous):

\[220(500)+4000\]\[110000+4000\]

OpenStudy (anonymous):

Is this it so far.

OpenStudy (anonymous):

yes for B

hero (hero):

Danyel, are you taking calculus?

OpenStudy (anonymous):

pre calc

OpenStudy (anonymous):

:) stop trying to rack up my good deed medals :)

hero (hero):

Which means you haven't studied derivatives yet

hero (hero):

I'm more interested in this buddy system idea of yours.

OpenStudy (anonymous):

its ok I just need to understand how to do this at the pre cal level.

OpenStudy (anonymous):

sn -

OpenStudy (anonymous):

howdid you get 220?

hero (hero):

Danyel, don't you have a formula for FC, VC, or TC?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

not seen that yet

hero (hero):

I already know what you're working on. You're working on a multi-step question and this is one of several things you're working on. The best thing to do is just post the entire document so that I can decipher it and explain to you how to derive the marginal cost using pre-calc methods.

OpenStudy (anonymous):

the question that is in the book is what I have posted. This is all it says.

OpenStudy (anonymous):

I just wanted to know the first step I figured out the rest of the question but I just wanted to know how she came up with the 220.

OpenStudy (anonymous):

The 220 just comes from the question?

OpenStudy (anonymous):

Basically this is a simple derivative (only one I know :)) since 220x is only term with variable - drop the x all other constants go to 0

OpenStudy (anonymous):

ok that is what I needed to know thank you so much

OpenStudy (anonymous):

you are welcome

OpenStudy (anonymous):

I like it when it is simple

OpenStudy (anonymous):

very :)

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