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Mathematics 22 Online
OpenStudy (anonymous):

Posting Question

OpenStudy (anonymous):

Anyone able to explain to me the math in-between?

razor99 (razor99):

u got the answer

OpenStudy (anonymous):

I got to 2(A'-(1/2)(h'b)/10 = b'

OpenStudy (anonymous):

I don't know what to do with the A', or h'

razor99 (razor99):

ohhh i get it yuo have to explain the sum right

OpenStudy (anonymous):

I just need to see how to get from 1/2(b'h) + 1/2(h'b) to -1.6 when h = 20, b = 10, A = 100 and the area of a triangle is A = bh/2

OpenStudy (anonymous):

is the problem the rate?

OpenStudy (anonymous):

the rate is given for the area. . .

OpenStudy (anonymous):

how to arrive b' ?

OpenStudy (anonymous):

substitute the value of A, b, h, h' , A' to find b' to the given derivative for the area of the rectangle. .

OpenStudy (anonymous):

here let me illustrate. . . |dw:1330937161185:dw|

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