Question

Can someone see if I did it right ?It looks wrong
*Curve sketching of limit approaching to infinity*

Answer 1

Wrong.

Answer 2

What did you say it approaches to as \(x\rightarrow \infty\)?

Answer 3

it juz says it is approaching + infinity

Answer 4

what did i do wrong?

Answer 5

That's incorrect. Have you learned L'Hopital's rule yet?

Answer 6

cuz i kinda think is wrong because my graph is not right...
my limit check says after x=1 is +ve, so it should touch x-intercept

but i found no x-intercept

Answer 7

my teacher didnt talk about it, so i guess no..

Answer 8

First, check what you got for \(f(1000)\) I'm pretty sure that's incorrect.

Answer 9

It definitely doesn't have any x-intercepts though.

Answer 10

I just plug it in my calculator though..it really gives 1.998, that means it is below the H.A

Answer 11

or am i suppose to use the derivative equation?

Answer 12

nm, I thought it said 1998. In that case, 1.998 sound correct.

Answer 13

oh ok, but if it is 1.998, then it should pass through x-intercept?

Answer 14

What I might do from here, is observe that it's below the horizontal asymptote, and observe that the slope of the function is positive after a certain point, thus, it must approach the HA as it goes to infinity.

Answer 15

It doesn't actually need to have an x-intercept, it could look like thisWhere the dotted line is some HA.