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Why is sec(-x) equivalent to sec x?
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secx is 1/cosx and cosx is an even function, meaninging cos(-x) = cos(x)
-x is in quadrant IV , x is in quadrant I, they are both positive for cosine , so as sec
What of cot and cosec?
In the unit circle, cosx >0 in the quadrand I and IV => cox = cos( -x)
cosec -> quadrant I, II cot -> quadrant I, III
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|dw:1331027929321:dw| See the above drawing. In the fourth quadrant, the distance AB is negative(measured in -y direction) while AC is positive(in +y direction) cos(-x)=OA/OB cos(x)=OA/OC Now, OC=OB(From congruency of triangles OAC and OAB) so cos(-x)=cosx similarly for secx(just the reciprocal) Do similarly for cot(-x) and cosec(-x), you will find that they are not equal to cotx and cosecx
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