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What is the vertex of the graph of y = −3x^2 − 4x + 2
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vertex:x = -b/2a ax^2 + bx + c b= -4 a= -3 vertex: x= -(-4)/2(-3) = 4/-6 = -2/3 y = -3(-2/3)2 - 4(-2/3) +2 http://hotmath.com/hotmath_help/topics/vertex-of-a-parabola.html
* I meant for that last line: y = -3(-2/3)^2 - 4(-2/3) +2
So y=-2
tyvm :D
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