Question

Need help solving:
log2(y+2)-1=log2(y-2)

Answer 1

the 2 being the base

Answer 2

2(y-2) = (y+2)
2y -y = 2 + 4
-> y = 6

Answer 3

chlorophyll i dont follow

Answer 4

1 = log2(2)

=> left hand side is

log2(y+2) - log2(2)

log laws state that this can be rewritten as

log2((y+2)/2)

so the equation reads

log2((y+2)/2)=log(y-2)

raising both 'onto' a power of 2 yields

(y+2)/2 = y-2

multiply by 2

y+2 = 2y - 4

rearrange for y;

6 = y

Answer 5

Awesome thank you!